Integrand size = 24, antiderivative size = 151 \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {a^3 x^5 \sqrt {a^2+2 a b x+b^2 x^2}}{5 (a+b x)}+\frac {a^2 b x^6 \sqrt {a^2+2 a b x+b^2 x^2}}{2 (a+b x)}+\frac {3 a b^2 x^7 \sqrt {a^2+2 a b x+b^2 x^2}}{7 (a+b x)}+\frac {b^3 x^8 \sqrt {a^2+2 a b x+b^2 x^2}}{8 (a+b x)} \]
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Time = 0.03 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {660, 45} \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {3 a b^2 x^7 \sqrt {a^2+2 a b x+b^2 x^2}}{7 (a+b x)}+\frac {a^2 b x^6 \sqrt {a^2+2 a b x+b^2 x^2}}{2 (a+b x)}+\frac {b^3 x^8 \sqrt {a^2+2 a b x+b^2 x^2}}{8 (a+b x)}+\frac {a^3 x^5 \sqrt {a^2+2 a b x+b^2 x^2}}{5 (a+b x)} \]
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Rule 45
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int x^4 \left (a b+b^2 x\right )^3 \, dx}{b^2 \left (a b+b^2 x\right )} \\ & = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \left (a^3 b^3 x^4+3 a^2 b^4 x^5+3 a b^5 x^6+b^6 x^7\right ) \, dx}{b^2 \left (a b+b^2 x\right )} \\ & = \frac {a^3 x^5 \sqrt {a^2+2 a b x+b^2 x^2}}{5 (a+b x)}+\frac {a^2 b x^6 \sqrt {a^2+2 a b x+b^2 x^2}}{2 (a+b x)}+\frac {3 a b^2 x^7 \sqrt {a^2+2 a b x+b^2 x^2}}{7 (a+b x)}+\frac {b^3 x^8 \sqrt {a^2+2 a b x+b^2 x^2}}{8 (a+b x)} \\ \end{align*}
Time = 0.91 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.68 \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {x^5 \left (56 a^3+140 a^2 b x+120 a b^2 x^2+35 b^3 x^3\right ) \left (\sqrt {a^2} b x+a \left (\sqrt {a^2}-\sqrt {(a+b x)^2}\right )\right )}{280 \left (-a^2-a b x+\sqrt {a^2} \sqrt {(a+b x)^2}\right )} \]
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Time = 2.77 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.34
method | result | size |
gosper | \(\frac {x^{5} \left (35 b^{3} x^{3}+120 a \,b^{2} x^{2}+140 a^{2} b x +56 a^{3}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}{280 \left (b x +a \right )^{3}}\) | \(52\) |
default | \(\frac {x^{5} \left (35 b^{3} x^{3}+120 a \,b^{2} x^{2}+140 a^{2} b x +56 a^{3}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}{280 \left (b x +a \right )^{3}}\) | \(52\) |
risch | \(\frac {a^{3} x^{5} \sqrt {\left (b x +a \right )^{2}}}{5 b x +5 a}+\frac {a^{2} b \,x^{6} \sqrt {\left (b x +a \right )^{2}}}{2 b x +2 a}+\frac {3 a \,b^{2} x^{7} \sqrt {\left (b x +a \right )^{2}}}{7 \left (b x +a \right )}+\frac {b^{3} x^{8} \sqrt {\left (b x +a \right )^{2}}}{8 b x +8 a}\) | \(100\) |
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Time = 0.23 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.23 \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {1}{8} \, b^{3} x^{8} + \frac {3}{7} \, a b^{2} x^{7} + \frac {1}{2} \, a^{2} b x^{6} + \frac {1}{5} \, a^{3} x^{5} \]
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Leaf count of result is larger than twice the leaf count of optimal. 218 vs. \(2 (105) = 210\).
Time = 0.60 (sec) , antiderivative size = 218, normalized size of antiderivative = 1.44 \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\begin {cases} \sqrt {a^{2} + 2 a b x + b^{2} x^{2}} \left (\frac {a^{7}}{280 b^{5}} - \frac {a^{6} x}{280 b^{4}} + \frac {a^{5} x^{2}}{280 b^{3}} - \frac {a^{4} x^{3}}{280 b^{2}} + \frac {a^{3} x^{4}}{280 b} + \frac {11 a^{2} x^{5}}{56} + \frac {17 a b x^{6}}{56} + \frac {b^{2} x^{7}}{8}\right ) & \text {for}\: b^{2} \neq 0 \\\frac {\frac {a^{8} \left (a^{2} + 2 a b x\right )^{\frac {5}{2}}}{5} - \frac {4 a^{6} \left (a^{2} + 2 a b x\right )^{\frac {7}{2}}}{7} + \frac {2 a^{4} \left (a^{2} + 2 a b x\right )^{\frac {9}{2}}}{3} - \frac {4 a^{2} \left (a^{2} + 2 a b x\right )^{\frac {11}{2}}}{11} + \frac {\left (a^{2} + 2 a b x\right )^{\frac {13}{2}}}{13}}{16 a^{5} b^{5}} & \text {for}\: a b \neq 0 \\\frac {x^{5} \left (a^{2}\right )^{\frac {3}{2}}}{5} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.06 \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} x^{3}}{8 \, b^{2}} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} a^{4} x}{4 \, b^{4}} - \frac {11 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a x^{2}}{56 \, b^{3}} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} a^{5}}{4 \, b^{5}} + \frac {13 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{2} x}{56 \, b^{4}} - \frac {69 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{3}}{280 \, b^{5}} \]
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Time = 0.28 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.48 \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {1}{8} \, b^{3} x^{8} \mathrm {sgn}\left (b x + a\right ) + \frac {3}{7} \, a b^{2} x^{7} \mathrm {sgn}\left (b x + a\right ) + \frac {1}{2} \, a^{2} b x^{6} \mathrm {sgn}\left (b x + a\right ) + \frac {1}{5} \, a^{3} x^{5} \mathrm {sgn}\left (b x + a\right ) + \frac {a^{8} \mathrm {sgn}\left (b x + a\right )}{280 \, b^{5}} \]
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Timed out. \[ \int x^4 \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\int x^4\,{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{3/2} \,d x \]
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